City-Data Forum Math idiot needs help with an equation..calling all math gurus.... (maths, grade)
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11-25-2011, 10:52 AM
 Location: SW Missouri 15,847 posts, read 30,364,616 times Reputation: 22356

Ok.

In the United States there are 254,212,610 privately owned and registered vehicles;

In the United States there are 223,877 privately owned and registered air craft

in the year 2009 there were 33,808 motor vehicle fatalities,

In the year 2009 there were 535 air craft fatalities.

What I am trying to figure out is this....

Based on the respective number of licensed vehicles, what is the annual death rate (for 2009) for accidents.

What is the percentage of people who are killed in each mode of transportation?

OMG I don't even know where to begin on this. I am really, hopeless when it comes to any sort of math stuff.

Your very kind and generous assistance is greatly appreciated. Thanks.

20yrsinBranson

11-25-2011, 11:10 AM
 11,151 posts, read 14,148,391 times Reputation: 18796
By my calculations, it's:

Auto deaths: 33,808/254,212,610 = 0.013%

Airplane deaths: 535/223,877 = 0.24%

11-25-2011, 11:14 AM
 Location: Arizona, The American Southwest 51,816 posts, read 29,901,232 times Reputation: 90880
Well, if every licensed vehicle (aircraft or automobile) has one registered owner, then to get the percentage you're looking for, use this equation:

(total number of fatalities / total number of registerd vehicles) * 100 - Do the math in the parenthesis first.

Example to get the percentage for registered aircraft:

(535 / 223877) = 0.0024 * 100 = .24% Percent (just less than 1/4 of a percent rounded off) .

11-25-2011, 11:19 AM
 Location: SW Missouri 15,847 posts, read 30,364,616 times Reputation: 22356
i'm holding out for the tie breaker.

20yrsinBranson

11-25-2011, 11:25 AM
 Location: Seattle bound 284 posts, read 421,315 times Reputation: 315
The great thing about maths is that there's only one right answer... ^_^ I have Dyscalculia, so I can't help you with the answers, but if two people come up with the same answer, it's probably right.

11-25-2011, 11:34 AM
 16,098 posts, read 17,899,425 times Reputation: 15895
Quote:
 Originally Posted by 20yrsinBranson i'm holding out for the tie breaker. 20yrsinBranson
.24 = 24%
.013 = 1.3%

The first person just forgot to multiply by 100 for the percentage.

11-25-2011, 12:10 PM
 Location: SW Missouri 15,847 posts, read 30,364,616 times Reputation: 22356
Hey, thanks everybody for helping out. I really appreciate it.

20yrsinBranson

11-25-2011, 12:18 PM
 3,252 posts, read 6,333,268 times Reputation: 1589
Quote:
 Originally Posted by wscottling The great thing about maths is that there's only one right answer... ^_^ I have Dyscalculia, so I can't help you with the answers, but if two people come up with the same answer, it's probably right.
-------------------------------------------------------------------

Well, in many cases there is more than one right answer.

For example,
X^2 = 4 has more than one answer for X.

11-25-2011, 12:30 PM
 11,151 posts, read 14,148,391 times Reputation: 18796
Quote:
 Originally Posted by nana053 .24 = 24% .013 = 1.3% The first person just forgot to multiply by 100 for the percentage.
No, I didn't. It's .24%, not 24%. Not every percentage is a whole number.

11-25-2011, 01:03 PM
 3,252 posts, read 6,333,268 times Reputation: 1589
Quote:
 Originally Posted by nana053 .24 = 24% .013 = 1.3% The first person just forgot to multiply by 100 for the percentage.
----------------------------------------------------------------------

'Dark of the Moon' is absolutely correct.

Nana053, remember learning percentages in 6th grade?
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