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Celsius doubles in cooking because the boiling point is 100 °C and the freezing point is 0 °C.
Completely logical way to measure temperature, referencing the freezing and vapor points of water.
HINT - Cheaters C to F conversion: [(C x 2) + 30]. It's not exact, but close enough for "quick and dirty" conversions. The actual formula is [(C x 9/5) + 32], if I'm not mistaken.
Completely logical way to measure temperature, referencing the freezing and vapor points of water.
HINT - Cheaters C to F conversion: [(C x 2) + 30]. It's not exact, but close enough for "quick and dirty" conversions. The actual formula is [(C x 9/5) + 32], if I'm not mistaken.
Read my post above about trying to find the half-boiling point on the Fahrenheit scale. I can't figure out the temperature correctly without converting 50 °C into Fahrenheit. I figured it out before but I didn't want to rummage through the posts.
Read my post above about trying to find the half-boiling point on the Fahrenheit scale. I can't figure out the temperature correctly without converting 50 °C into Fahrenheit. I figured it out before but I didn't want to rummage through the posts.
Hmm, [(50 C x 2) + 30] = 130 degrees, but that calculation isn't exact science. The exact calculation would be [(50 C x 9/5) + 32] = 127. Is that close to 1/2 boiling F?
Hmm, [(50 C x 2) + 30] = 130 degrees, but that calculation isn't exact science. The exact calculation would be [(50 C x 9/5) + 32] = 127. Is that close to 1/2 boiling F?
But according to Google, it's actually 122 °F, which is the correct answer. There is a step I missed that brings it down to 122 °F but I can't figure it out. See how hard Fahrenheit is? (Plus it's hard to spell phonetically.)
But according to Google, it's actually 122 °F, which is the correct answer. There is a step I missed that brings it down to 122 °F but I can't figure it out. See how hard Fahrenheit is? (Plus it's hard to spell phonetically.)
Hmm, [(50 C x 2) + 30] = 130 degrees, but that calculation isn't exact science. The exact calculation would be [(50 C x 9/5) + 32] = 127. Is that close to 1/2 boiling F?
Somewhere your math is wrong. It's 122, not 127. See above.
The down-and-dirty method is really best for figuring out commonly experienced atmospheric temperatures. It's dead-accurate at exactly 10c/50F (both the quick-and-dirty formula and the actual formula yield the exact same answer); and he further away from that into "temperature extremes" you go, the less accurate it becomes.
But according to Google, it's actually 122 °F, which is the correct answer. There is a step I missed that brings it down to 122 °F but I can't figure it out. See how hard Fahrenheit is? (Plus it's hard to spell phonetically.)
Yeah, I agree with you on Fahrenheit. Just like "using a king's foot" as a unit of measure, as you pointed out in an earlier post, it's strange at best.
I don't want to go metric. It's not because I don't think it's "cleaner" or beneficial because it's mostly global. I don't want to go metric, because I don't think I could stand my father complaining about it. He's a machinist for automobiles and he'd have to adjust everything he currently works with. Boy, everytime a new car has a metric nut/bolt on it, I sure hear a lot of cussing!
I don't want to go metric. It's not because I don't think it's "cleaner" or beneficial because it's mostly global. I don't want to go metric, because I don't think I could stand my father complaining about it. He's a machinist for automobiles and he'd have to adjust everything he currently works with. Boy, everytime a new car has a metric nut/bolt on it, I sure hear a lot of cussing!
I don't drive American cars but I think they have been metric since the late 70's. My Camry use 10 mm bolts and the only things that are non-metric are the spedometer (except for the inner km markings) and the wheels (common for all cars).
Will he start his Anti-Catholic epithets when we are talking about the Gregorian Calendar? Will he support the crown by stopping decimalized currency in its tracks? Or will he support the Republic by using metric instead of the King's foot?
I don't drive American cars but I think they have been metric since the late 70's. My Camry use 10 mm bolts and the only things that are non-metric are the spedometer (except for the inner km markings) and the wheels (common for all cars).
Will he start his Anti-Catholic epithets when we are talking about the Gregorian Calendar? Will he support the crown by stopping decimalized currency in its tracks? Or will he support the Republic by using metric instead of the King's foot?
Haha, nice. There are still parts on my old 1994 Pontiac that aren't metric, but I don't know the details. All I know is he's Italian, and you don't want to hang out with him in the garage when that good ol' metric gets in his way. He's bound to put a king's foot right up where the sun don't shine
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