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Do you get similar departures from average for record highs/lows in summer?
Here are our record highs/low highs for the summer months vs the averages:
June:
Average high: 16.9C
Record high: 29C (rounded) - 12.1C above
Record low high: 7C (rounded) - 9.9C below
July:
Average high: 19.1C
Record high: 31.0C - 11.9C above
Record low high: 10.7C - 8.4C below
August:
Average high: 18.7C
Record high: 31.6C - 12.9C above
Record low high: 10.3C - 8.4C below
============================
You can see from the red graph, that it's symmetrical and with one peak, suggesting the mean and median are close.
Hmm. But checking:
June:
Average high: 78.2°F
Record high: 101°F
Average yearly extreme high: 91°F
Record low high: 46°F
Average yearly extreme low high: 61°F
July:
Average high: 83.0F
Record high: 104°F
Average yearly extreme high: 93°F
Record low high: 59°F
Average yearly extreme low high: 70°F
August:
Average high: 81.0°F
Record high: 100°F
Average yearly extreme: 91°F
Record low high: 56°F
Average yearly extreme low high: 67°F
I added average yearly extreme as the sample size is greater. But there's a slight skew in the opposite direction — slightly more extreme colder than average temperatures than warmer. But outside of extremes, the distribution is symmetrical and mean = median. Those days with cool highs are typically from very cloudy times when it rains all day.
MATLAB for those charts, I switch back and forth between the two. Computer code is more efficient for large datasets, especially if doing similar graphs and processing. R is a good free alternative.
I used Excel this time but I can highly recommend "R" (even better with the RStudio environment) for statistical things. It's actually not complicated but probably even more unclear than Excel for a beginner.
MATLAB for those charts, I switch back and forth between the two. Computer code is more efficient for large datasets, especially if doing similar graphs and processing. R is a good free alternative.
For those who like MATLAB, isn't OCTAVE a better free alternative?
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