Can you have 9 foot ceilings with 5/12 roof pitch?
Please register to participate in our discussions with 2 million other members - it's free and quick! Some forums can only be seen by registered members. After you create your account, you'll be able to customize options and access all our 15,000 new posts/day with fewer ads.
Is this for an open beam or cathedral type ceiling or are you wondering about available height in an attic space?
A 5/12 ceiling pitch means that it goes up five inches for every foot. So, nine feet in inches is 108". Divide that by the five inches per foot lineal distance for the 5/12 pitch roof and at the end of 21.6 feet, you'll have your nine feet to the top of the roof slope. If you have a roof with two slopes (hip, gable, etc.), then you'll need approximately 43' of house width to get to a 9' height at the peak of the roof.
If you're only concerned about the height of a flat ceiling above a room, then that has nothing to do, usually, with the roof above it.
It seems to me that there is some factor that isn't being mentioned that would lead you to ask the question. Why would you think you couldn't have 9' ceilings with a 5/12 roof pitch? Is there some height limit you are working with?
It seems to me that there is some factor that isn't being mentioned that would lead you to ask the question. Why would you think you couldn't have 9' ceilings with a 5/12 roof pitch? Is there some height limit you are working with?
No, I just assumed it would be attic space taken away and wasn't sure it would permit for it. From the helpful responses, I learned differently
If the walls in a new structure are going to be 9'1" high, and the pitch of the vaulted ceiling is 5:12, what is the height of the "vault" (the highest part of the peak)?
I know that I should be able to do a simple calculation on this one, but I'm stuck despite searching online.
If the walls in a new structure are going to be 9'1" high, and the pitch of the vaulted ceiling is 5:12, what is the height of the "vault" (the highest part of the peak)?
I know that I should be able to do a simple calculation on this one, but I'm stuck despite searching online.
Thanks!
No calculation possible without knowing the distance, horizontal dimension, between the 9’-1” wall and the wall opposite that wall where the ceiling will sit and what is the height of the opposing wall?
A cathedral ceiling is different than a vaulted ceiling and in order to determine a height, you really need a sketch with dimensions since a vaulted ceiling could be offset so the peak may not be centered between the two walls like a cathedral ceiling would be.
Using my garage as an example: 30' wide, 8' wall, 5/12 pitch. Building height 14'3". If I just want the height of the vault I subtract the 8' wall and get 6'3".
Try it with your dimensions.
Or, you can stand on a ladder and measure from the ridge to the floor.
My brother bought a HUD home years ago. The person who had the home before him decided he wanted cathedral ceilings and must have taken a chain saw to all the rafters. Of course one of the conditions on rehab was replace roof, or year down the whole house. That's one way to have taller ceilings if you want your house to collapse.
Please register to post and access all features of our very popular forum. It is free and quick. Over $68,000 in prizes has already been given out to active posters on our forum. Additional giveaways are planned.
Detailed information about all U.S. cities, counties, and zip codes on our site: City-data.com.
Please register to participate in our discussions with 2 million other members - it's free and quick! Some forums can only be seen by registered members. After you create your account, you'll be able to customize options and access all our 15,000 new posts/day with fewer ads.
