Densest City That Could Be Created Using America's Densest Neighborhoods (beach, land)

[BajanYankee]

Using non-NYC neighborhoods, what is the densest city that could be achieved using America's densest neighborhoods. For example...

The Haight - 10,601 (.31 sq. mi.)
The Tenderloin - 25,067 (.35 sq. mi.)
Koreatown (LA) - 124,281 (2.7 sq. mi.)
Westlake - 108,839 (2.72 sq. mi.)
Near North Side - 80,484 (2.72 sq. mi.)

All of these areas combined to form a single city would have a population of 349,272 in 8.8 square miles (39,690 ppsm). That's denser than 4 of the 5 Boroughs of New York City. But how many more neighborhoods could be added before this hypothetical city's density falls below that of Queens (21,333 ppsm)?

[JMBX]

I doubt you could even get to Queens-level population without dropping below 21.3K ppsm, although I bet it'd relatively close if you used all of the Chicago Lakefront, all of near-Westside LA, all of Center City and South Philly, all of San Francisco E of Van Ness + The Mission, inner Boston, and inner DC.

If NYC-adjacent hoods count as "non-NYC" then you could add much of Hudson County, Passaic, and parts of Yonkers and that might get you to Queens population. That's a very interesting question though, the next time I'm really bored I think I'll give it a go.

[BajanYankee]

Originally Posted by JMBX

I doubt you could even get to Queens-level population without dropping below 21.3K ppsm, although I bet it'd relatively close if you used all of the Chicago Lakefront, all of near-Westside LA, all of Center City and South Philly, all of San Francisco E of Van Ness + The Mission, inner Boston, and inner DC.

By adding the Mission, Chinatown, Back Bay, Center City, and Columbia Heights, we get a total population of 550,818 in 13.48 sq. miles (40,861 ppsm). Still higher than all NYC boroughs except Manhattan.

[rnc2mbfl]

North Bay Village (an actual separate city in Miami): .3322 sq. mile of land and 7871 people for 23,693 ppl/sm

[BajanYankee]

Originally Posted by BajanYankee

Using non-NYC neighborhoods, what is the densest city that could be achieved using America's densest neighborhoods. For example...

The Haight - 10,601 (.31 sq. mi.)
The Tenderloin - 25,067 (.35 sq. mi.)
Koreatown (LA) - 124,281 (2.7 sq. mi.)
Westlake - 108,839 (2.72 sq. mi.)
Near North Side - 80,484 (2.72 sq. mi.)

All of these areas combined to form a single city would have a population of 349,272 in 8.8 square miles (39,690 ppsm). That's denser than 4 of the 5 Boroughs of New York City. But how many more neighborhoods could be added before this hypothetical city's density falls below that of Queens (21,333 ppsm)?

Center City - 61,198 (2.3 sq. mi.)
Dupont Circle - 17,307 (0.88 sq. mi.)
Back Bay - 11,737 (0.42 sq. mi.)
North End - 9,312 (.27 sq. mi.)
Pico Union - 39,336 (1.6 sq. mi.)
Columbia Heights - 33,979 (1.3 sq. mi.)
Castro - 12,536 (0.53 sq. mi.)
Chinatown (SF) - 10,996 (1.7 sq. mi.)
North Beach - 19,084 (0.49 sq. mi.)
Nob Hill - 19,964 (0.31 sq. mi.)
Russian Hill - 14,105 (0.4 sq. mi.)
Pacific Heights - 23,545 (0.77 sq. mi.)
The Mission - 43,754 (1.48 sq. mi.)
Mission Dolores - 11,613 (0.28 sq. mi.)

Updated total: 677,758 people in 21.53 sq. mi. (31,479 people per sq. mi.)