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Old 04-10-2020, 11:54 AM
 
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It seems at this juncture that approximately 1% of those who are infected succumb to the virus (RIP), and a study from Italy showed that 99.2% of those dying had at least one serious underlying condition. So, what is the percentage likelihood that a healthy adult would catch the disease and then succumb to it? Would it be 1% x .08%?

P.S. I was horrible with word problems in junior high and still would be. (I have other talents.)

 
Old 04-10-2020, 12:15 PM
 
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So using your numbers, 1/100 die from it, out of those 992/1000 had at least one serious underlying condition, meaning 8/1000 would be considered "healthy" with no known underlying condition.

Therefore 8/100,000 or 1/12,500 so-called "healthy" people with no known underlying condition would die from the virus, on average.
 
Old 04-10-2020, 12:16 PM
 
Location: Santa Monica
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I graduated from government schools. No idea.
 
Old 04-10-2020, 12:16 PM
 
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Quote:
Originally Posted by cjseliga View Post
So using your numbers, 1/100 die from it, out of those 992/1000 had at least one serious underlying condition, meaning 8/1000 would be considered "healthy" with no known underlying condition.

Therefore 8/100,000 or 1/12,500 so-called "healthy" people with no known underlying condition would die from the virus, on average.
Pretty good odds of survival.
 
Old 04-10-2020, 12:19 PM
 
Location: Morrison, CO
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Originally Posted by ncguy50 View Post
Pretty good odds of survival.
Yes but if we can just save one life out of 10,000,000,000,000,000,000,000,000,000, it's worth ending the world as we know and creating extreme hardship and even death for the rest of us.
 
Old 04-10-2020, 12:25 PM
 
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Originally Posted by pilot1 View Post
yes but if we can just save one life out of 10,000,000,000,000,000,000,000,000,000, it's worth ending the world as we know and creating extreme hardship and even death for the rest of us.
:d
 
Old 04-10-2020, 12:34 PM
 
36,539 posts, read 30,885,552 times
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Quote:
Originally Posted by Rachel976 View Post
It seems at this juncture that approximately 1% of those who are infected succumb to the virus (RIP), and a study from Italy showed that 99.2% of those dying had at least one serious underlying condition. So, what is the percentage likelihood that a healthy adult would catch the disease and then succumb to it? Would it be 1% x .08%?

P.S. I was horrible with word problems in junior high and still would be. (I have other talents.)
Apparently, according to some, this does not apply if you are a cashier. If customers pick up a can of hair spray while shopping for milk they will put the cashiers life in grave danger. Probably raises tha %age to 60%.
 
Old 04-10-2020, 12:35 PM
 
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It may be that many had a serious underlying condition. The problem is - you do too. Lots of people do. Maybe 150M. That's because they consider high blood pressure a serious underlying condition. Diabetes. Others. Yes, of course, cancer too, COPD, genuinely serious conditions. Not a huge statistical change between cancer, diabetes, or high BP, though. So don't pretend High BP isn't serious. It is.



Since the longer you live, the more likely you are to have one of these conditions, I don't think this data is a surprise.



So - if you're between the ages of 50 -59 - your chance of Death is about 1%. Younger? Much, much lower, something like 0.2%, while if you're older...it's much more than 1%. Maybe 15% of you're over 80.



Another - much better way to look at this is - regardless of your age - if you catch this - you have an 85% chance of living. 99.8% if you're under 50. 500 people catch it, 1 dies. You're at a much higher risk from just about anything else. For an individual - it's a small chance - but for a population - that's 350,000 people. Way. Too. Many. (Again that's people under 50.)
 
Old 04-10-2020, 12:38 PM
 
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Quote:
Originally Posted by cjseliga View Post
So using your numbers, 1/100 die from it, out of those 992/1000 had at least one serious underlying condition, meaning 8/1000 would be considered "healthy" with no known underlying condition.

Therefore 8/100,000 or 1/12,500 so-called "healthy" people with no known underlying condition would die from the virus, on average.
The REAL trick is determining how meaningful the 1% number is. If the disease is being chronically under-diagnosed, then the mortality rate is lower (assuming that the untested positive rate is higher than the untested death rate, which is quite reasonable) and quite likely significantly lower.
 
Old 04-10-2020, 12:39 PM
 
Location: Oklahoma
17,804 posts, read 13,708,449 times
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Quote:
Originally Posted by Rachel976 View Post
It seems at this juncture that approximately 1% of those who are infected succumb to the virus (RIP), and a study from Italy showed that 99.2% of those dying had at least one serious underlying condition. So, what is the percentage likelihood that a healthy adult would catch the disease and then succumb to it? Would it be 1% x .08%?

P.S. I was horrible with word problems in junior high and still would be. (I have other talents.)

OK, so 18,000 people have died in the US. .08% of those 18K were "healthy". 18,000 x .0008= 14.4.
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